Question

A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10^−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 25.0 mL of NaOH. Express your answer numerically.

Name: 1 2 a 520 ml volume of 035 m ch3cooh ka18105 is titrated with 040 m naoh calculate the ph after the addition of 250 ml of naoh express your answer numerically 71508
Uploaded: 2023-08-29T15:40:55-08:00
Duration: 4 min 35 s
Channel: Adi S
Description: 1 2 a 520 ml volume of 035 m ch3cooh ka18105 is titrated with 040 m naoh calculate the ph after the addition of 250 ml of naoh express your answer numerically 71508

          A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10^−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 25.0 mL of NaOH.
Express your answer numerically.

Added by Crystal W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

08/29/2023

Step 1

moles of CH3COOH = volume × concentration = 0.052 L × 0.35 mol/L = 0.0182 mol moles of NaOH = volume × concentration = 0.025 L × 0.40 mol/L = 0.010 mol 2) Now, we need to find the moles of CH3COOH and CH3COO- after the reaction. moles of CH3COOH = initial moles Show more…

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A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10^−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 25.0 mL of NaOH. Express your answer numerically.