Show all work for full credit. 1. [2.5 pts] [2.5 pts] In...

Show all work for full credit. 1. [2.5 pts] [2.5 pts] In Drosophila, the autosomal recessive bw allele causes a dark brown eye, and the unlinked autosomal recessive st allele causes a bright scarlet eye. A homozygote for both genes has a white eye. These genotypes produce these phenotypes: st+/st+; bw+/bw+=red eye (wild type) st+/st+; bw/bw=brown eye st/st; bw+/bw+=scarlet eye st/st; bw/bw=white eye Construct a hypothetical biosynthetic pathway and describe how the gene products interact and why the different mutant combinations have different phenotypes.

Transcript

00:02 Hello students, the concept given in the question is about monohybrid cross where a single characteristic has been considered.

00:13 What is required for us is to find out or to predict the offspring of f1 and f2 generation with respect to the three parental crosses given in the question.

00:27 Okay, yes, let us get into the explanation.

00:30 Well, according to the given data, what can be indicated is there is a single characteristic called eye color which is being given in rosophila.

00:41 So here there is of three types of phenotypes that's nothing but the wild type.

00:47 Let's consider it's, you know, the gene or the allele which is controlling it to be w &w, as it is a deployed organism and it is homozygis.

00:58 And brown color, okay, to be.

01:05 And b and scarlet color.

01:11 There's a bluess and the blue s, okay.

01:14 And then they also said that there is no pigmentation at all on cross of the homozygous brown and scarless colors.

01:25 It leads to the white color which will keep it as this heterozygous condition.

01:31 Yes, this is what can be indicated.

01:34 Now knowing this, you know, the gene combinations or the allele combinations of a different phenotypes here of i trailer.

01:43 Let us understand what would be the offspring phenotype with respect to the three parental crosses.

01:50 Yes, just look into that.

01:53 So the first one says about the cross between wild type and the white colored ones.

02:02 So wild type here is w &w and white is wb and wb.

02:07 Right, the image formed.

02:09 Okay, this is the parental generation.

02:11 The image form will be w and w and this to be wb and wb.

02:19 Right? so on the cross of this what will we get? it's quite simpler when you do it in this way.

02:29 I've just highlighted the other cross in a dotted line.

02:33 So this will all be yes.

02:43 Now here as you already know that the brown and the scarlet are the recessive one, then the same to be the capital w no all of it will be wilder, that is the dominant ones.

02:55 So as it is present in all of it, it will suppress the brown and the scarlet colors.

03:02 Yes, so obviously all of it are wild in this specific kind of cross...

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