The diameter of the mild steel core is 67mm, so its radius is 33.5mm.
The area of the mild steel core, $A_{ms}$, is given by:
$$A_{ms} = \pi r^2 = \pi (33.5 \times 10^{-3})^2 = \pi (0.0335)^2 \approx 3.525 \times 10^{-3} m^2$$
The outside diameter of the alloy
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