1. A composite bar is 350 mm long and consists of a copper tube butt-welded to the end face of a steel bar. The tube dimensions are 30 mm diameter x 20 mm bore x 200 mm long, and the steel bar is 30 mm diameter and 150 mm long. If the bar supports an axial force of 4 kN, determine (a) The stresses in the copper and the steel. (b) The change in length of the composite bar. For steel, E = 200 GN/m² ; for copper, E = 120 GN/m².
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For the copper tube: The area of the copper tube can be calculated using the formula for the area of a circle: A = πr^2, where r is the radius of the tube. Given that the diameter of the tube is 30 mm, the radius is 15 mm or 0.015 m. So, the area of the copper Show more…
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1. A steel rod of 25 mm diameter is enclosed centrally in a copper hollow tube of external diameter 40 mm and internal diameter 30 mm. The composite bar is then subjected to an axial load of 4500 N.If the length of each bar is equal to 130 mm, calculate:1. The stress in the rod and the tube2. Load carried by each bar.Take Es=2.1x105 N/mm2 and Ec=1.1x105 N/mm2
A steel rod of 25 mm diameter is enclosed centrally in a copper hollow tube of external diameter 40 mm and internal diameter 30 mm. The composite bar is then subjected to an axial load of 4500 N. If the length of each bar is equal to 130 mm, calculate: 1. The stress in the rod and the tube 2. Load carried by each bar. Take Es = 2.1x105 N/mm2 and Ec = 1.1x105 N/mm2
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