00:01
In this problem we are going to do some stretching with springs.
00:05
So we have two questions.
00:07
Let's get started with the first one.
00:10
It says a force of 220 newtons stretches a spring 0 .12 meters.
00:20
So using this information we are going to find a spring constant then we are going to calculate the force that stretches the spring by 0 .16 meters.
00:31
So let's remember the hook slow.
00:35
We have applied force equal to spring constant times the displacement of the spring from its natural length or simply the stretching length of the spring.
00:46
So we are given when f is equal to 220, delta x is equal to 0 .12.
00:57
So using this, we find that k is equal to 1 ,80033 plus 0 .33 per meter.
01:10
Okay, now let us compute the amount of force that was stretched a spring by 0 .16 meters.
01:19
So f is equal to k times 0 .16...