1.) A man doing push-ups pauses at the position shown in the figure. His mass is m = 72 kg, and the position of the center of mass is shown in the figure. Determine the normal force exerted by the floor on: (a) Each hand (b) Each foot.
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Given: - Mass of the man (M) = 72 kg - Gravitational acceleration (g) = 9.8 m/s^2 - Normal force on each foot (N2) = 108.22 N Using the equation: N1 + 2N2 = Mg Substitute the values: N1 + 2(108.22) = 72 * 9.8 Solve for N1: N1 = 705.6 - 216.44 = 489.16 N Show more…
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