1. A Pelton wheel has a mean bucket speed of 35 m/s with a jet of water flowing at the rate of 1 m³/s under a head of 270 m. The buckets deflect the jet through an angle of 170°. Calculate the power delivered to the runner and the hydraulic efficiency of the turbine. Assume the coefficient of velocity as 0.98. [Ans. 2523.8 kW, 95.3%]
Added by Melanie L.
Step 1
\[ v = C_v \sqrt{2gH} \] Given: \( C_v = 0.98 \), \( g = 9.81 \, m/s^2 \), \( H = 270 \, m \). \[ v = 0.98 \times \sqrt{2 \times 9.81 \times 270} = 0.98 \times \sqrt{5297.4} = 0.98 \times 72.79 = 71.33 \, m/s \] --- Show more…
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