00:01
For question one, we would like to find at what time the two stones are the same height.
00:06
So we can write an expression for the first stone.
00:09
So for the first stone, we can set h1 is equal to ut minus one -half jt, and we have our value for you, so we can plug that in.
00:18
For h2, which is a second stone, we'll have the same velocity, but our t is t minus 1 .370.
00:28
So if we want to be at the same height, we need to set these.
00:31
These two expressions equal to each other.
00:33
If we do, we should get 47 .90 t minus one half gt squared is equal to 47 .90 t minus 1 .370 minus 1 .370, minus 1 .370 squared.
00:47
We'll get negative 1 half gt squared is equal to negative 65 .62 minus 1 .7g t squared plus 1 .876 minus 2 .74t.
00:57
We can go ahead redistribute...