00:01
Hello, let's have a look on the question.
00:02
Here we have given ka1 that is equals to 6 .46 into 10 to the power minus 3.
00:08
Ka2 that is equals to 1 .15 into 10 to the power minus 7.
00:12
Ka3 that is equals to 3 .16 into 10 to the power minus 12.
00:17
As we know, pca is equal to negative of log ka.
00:24
So, pka1 that is equals to negative of log, 6 .46 into 10 to the power minus 3 comes out to be 2 .189.
00:39
P .k .a2, that is equals to negative of log 1 .15 into 10 to the power minus 7, that is equals to 6 .939.
00:52
P .a3, that is equal to negative of log, 3 .16 into 10 to the power minus 5 .5.
01:01
Comes out to be 11 .50.
01:08
A part...