00:01
Okay, we have some information about a hydrate.
00:04
They have some data, and they've already done my hydrate information, and we can see that my hydrate has a mass of 0 .9935 grams.
00:22
And this was already calculated.
00:25
I'm just going to double check this, and 0 .557814.
00:41
Well, the number they've got is wrong.
01:03
So they've got, i better write these down.
01:11
Crucible, lid, and hydrate.
01:20
You have written down 55 .7814 grams.
01:30
The crucible and lid, lid only, you've written down 55 .224 grams.
01:47
The hydrate should be the difference on these two.
01:53
0 .7814 .224 is 0 .5574.
02:05
You wrote down 0 .9935 for that one.
02:21
Okay, then after the first weighing, i'm not going to even worry about the first weight.
02:26
I'm going to go to the third.
02:28
You didn't put anything in there in the rights.
02:33
First heating, second heating, third heating.
02:35
Okay, then, so the crucible and the anhydrous salt, 55 .7436, and the empty crucible and lid.
03:16
Oh, this should be 246 up here, i think.
03:23
I think you've got a six in the wrong spot.
03:26
2246, so that'll change that.
03:37
5568.
03:48
And i feel like you never wrote down your crucible lid and hydrate.
04:01
You wrote 50.
04:02
For my third heating, you wrote 55 .246 again, 2246 .0 .4192.
04:23
55 .75 .76 minus 55 .246 .519.
04:33
So this is hardly any difference at all.
04:35
Okay.
04:36
Well, we'll deal with this as we get there.
04:43
So i want to make a note here.
04:50
Well, i won't make a note yet.
04:52
It doesn't look for like very good data.
04:56
It does say that you have copper two sulfate.
05:03
And i'm going to get to my molar mass down, get my molar mass of copper two sulfate.
05:12
Copper two sulfate is 159 .61.
05:18
So i can go to moles.
05:30
And then this is my mass of dry salt.
05:36
And my mass of water will be equal to 0 .5568 grams minus 0 .5190 grams equals 0 .0378 grams of water.
06:11
Next we're going to turn these into moles.
06:16
So i've got, for my water, i'm going to take 0 .03378 grams.
06:26
Times 18 .02 grams per mole.
06:32
For my anhydrous salt, i will take 0 .5190 divided by 159 .61 .61 grams per mole.
07:03
Let's see what this equals...