Question

1. Consider the function $N(t) = \frac{250}{1 + 4e^{2t}}$ (a) Compute $N(0)$. (b) Compute $\lim_{t \to \infty} N(t)$ 

          1. Consider the function
$N(t) = \frac{250}{1 + 4e^{2t}}$
(a) Compute $N(0)$.
(b) Compute $\lim_{t \to \infty} N(t)$
1. Consider the function N(t) = (250)/(1 + 4e^2t) (a) Compute N(0). (b) Compute limt →∞ N(t)

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Consider the function N(t) = 1 + 4e^(2t) (a) Compute N(0) (b) Compute lim N(t) as t approaches 8
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Transcript

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00:01 We need to evaluate the limit here limit n tends to infinite okay sigma of j equal to 1 to n 4 j square divided by here it is actually n cube so we can write it as a limit n tends to infinite then here 4 divided by n cube will be considered as here constant so now because we are given here sigma from j to j equal to 1 to n so here we'll write that sigma j equal to 1 to n it is j square okay so limit n tends to infinite 4 divided by n cube times of so it's a value is like we are supposed to know that sigma n equal to 1 to n n square is equals to obviously 1 divided by n sorry 1 divided by 6 times it is here 1 divided by 6 times n times n plus 1 times 2n plus 1 okay so we can write here 1 by n times n 1 by 6 times n…
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