Question

Find an equation of the tangent line to the graph of $y = \frac{-8x}{x^2 + 1}$ at the origin and at the point $(1, -4)$.

Name: Find an equation of the tangent line to the graph of y = (-8x)/(x^2 + 1) at the origin and at the point (1, -4).
Uploaded: 2023-04-06T17:47:59-08:00
Duration: 1 min 22 s
Channel: Sri K
Description: Find an equation of the tangent line to the graph of y = (-8x)/(x^2 + 1) at the origin and at the point (1, -4).

          Find an equation of the tangent line to the graph of $y = \frac{-8x}{x^2 + 1}$ at the origin and at the point $(1, -4)$.

Added by Angela C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

04/06/2023

Step 1

The derivative of y with respect to x can be found using the quotient rule: y' = [(x^2+1)(-8) - (-8x)(2x)] / (x^2+1)^2 y' = (-8x^2 - 8 + 16x^2) / (x^2+1)^2 y' = (8x^2 - 8) / (x^2+1)^2 y' = 8(x^2 - 1) / (x^2+1)^2 Show more…

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