Question

(1 point) Use the Laplace transform to solve the following initial value problem: $y'' - 9y' + 20y = 0$, $y(0) = 2$, $y'(0) = 1$ (1) First, using Y for the Laplace transform of $y(t)$, i.e., $Y = \mathcal{L}(y(t))$, find the equation you get by taking the Laplace transform of the differential equation to obtain $= 0$ (2) Next solve for $Y = $ (3) Now write the above answer in its partial fraction form, $Y = \frac{A}{s - a} + \frac{B}{s - b}$ (NOTE: the order that you enter your answers matter so you must order your terms so that the first corresponds to $a$ and the second to $b$, where $a < b$. Also note, for example that $-2 < 1$) $Y = $ (4) Finally apply the inverse Laplace transform to find $y(t)$ $y(t) = $

          (1 point)
Use the Laplace transform to solve the following initial value problem: $y'' - 9y' + 20y = 0$, $y(0) = 2$, $y'(0) = 1$
(1) First, using Y for the Laplace transform of $y(t)$, i.e., $Y = \mathcal{L}(y(t))$,
find the equation you get by taking the Laplace transform of the differential equation to obtain
$= 0$
(2) Next solve for $Y = $
(3) Now write the above answer in its partial fraction form, $Y = \frac{A}{s - a} + \frac{B}{s - b}$
(NOTE: the order that you enter your answers matter so you must order your terms so that the first corresponds to $a$ and the second to $b$, where
$a < b$. Also note, for example that $-2 < 1$)
$Y = $
(4) Finally apply the inverse Laplace transform to find $y(t)$
$y(t) = $

$(1 point) Use the Laplace transform to solve the following initial value problem: y” - 9y' + 20y = 0, y(0) = 2, y'(0) = 1 (1) First, using Y for the Laplace transform of y(t), i.e., Y = ℒ(y(t)), find the equation you get by taking the Laplace transform of the differential equation to obtain = 0 (2) Next solve for Y = (3) Now write the above answer in its partial fraction form, Y = (A)/(s - a) + (B)/(s - b) (NOTE: the order that you enter your answers matter so you must order your terms so that the first corresponds to a and the second to b, where a < b. Also note, for example that -2 < 1) Y = (4) Finally apply the inverse Laplace transform to find y(t) y(t) =$

Added by Daniel P.

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