Given a population in Hardy-Weinberg equilibrium with allele frequencies A = 0.9 and a = 0.1, determine the frequencies of the three genotypes AA, Aa, and aa. Answer key: P^2 + 2pq + q^2 = 1, p = 0.9, q = 0.1, p^2 = 0.81, 2pq = 0.18, q^2 = 0.01.
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Given a population in Hardy-Weinberg equilibrium with allele frequencies A = 0.9 and a = 0.1, determine the frequencies of the three genotypes AA, Aa, and aa. Using the Hardy-Weinberg equilibrium equation: $p^2 + 2pq + q^2 = 1$ $p = 0.9$ and $q = 0.1$ AA: $p^2 Show more…
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