1) Given a right triangle 30º-60º-90º whose shorter leg is 1 cm, find sin 30º, cos 30º and tan 30º. 2) If $\sin \theta = \frac{\sqrt{3}}{2}$, what is the value of $\sin^2 \theta + \cos^2 \theta$? 3) In $\triangle ABC$, $\angle C = 90^\circ$ and $\tan A = \frac{2\sqrt{6}}{5}$. Find cos B. (Source: MMC 2017, Elimination Round Grade 9, Item # 50)
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The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. So, using the Pythagorean theorem, we have: (1 cm)^2 + (x cm)^2 = (900 cm)^2 1 + x^2 = Show more…
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Let a be the shorter leg of a 30° - 60° - 90° Triangle Sin 30° = csc 30° = Cos 30° = sec 30° = Tan 30° = cot 30° = Let a be the shorter leg of a 30° - 60° - 90° Triangle Sin 60° = csc 60° = Cos 60° = sec 60° = Tan 60° = cot 60° =
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