00:01
So the first structure we will draw is p dichlorobenzene.
00:09
And this also, it could be written out as 1 -4 dichlorobinzy.
00:16
That is what the p means.
00:18
And its structure looks like that.
00:23
So you have your aromatic ring and then 1 in 4, on 1 of 4 carbon is the chlorine.
00:33
So next we have p, iodinell.
00:40
Again, the substitutes are on carbon 1 and 4, so we have our ring.
00:47
It's aromatic.
00:50
So right here you would have the h2, and right here is the iodide.
00:59
For c, we have o, bromo, nitrobenzine, so there we have our benzene ring...