00:01
Hi, here in this given problem, in the first part of the problem we have to find the resistors which are in series combination in different circuits.
00:11
So first of all in the circuit a, it is clear that 5 kilo -on and 7 -kilome, these are in series combination.
00:33
Circuit b here 800 om and 12 hundred om these are in series in one of the branch and 300 om are in series in another branch and 300 oom are in series in another branch then in the third one in circuit c there are 15 om and in the third circuit c yes there are 15 and 35 and 25 and 25 15 om 15 35 om 15 35 and 25 and 25 and 25 and 25 oom 15 35 and 25 and 25 these are in series in one branch and 10 om and 40 om are in series in another branch.
02:01
Then in circuit d in the fourth circuit here 50 om, 90 om and these are in one branch, series in one branch and 80 oom and 70 oom are in series in another branch.
02:34
Now we have to find equivalent resistances of all these circuits in the second part of the problem.
02:43
So, starting from circuit a 5 kilo -oom plus 7 kilo -oom, these are in series, so it becomes 12 kilo -oom.
02:57
Then this 12 kilo -oom is in parallel with the 6 kilo -oom.
03:03
So net resistance of parallel combination, that is 6 into 12, divided by 6 plus 12, and it comes out to be equal to 4 kilo -oom.
03:14
And finally, this 4 kilo -oom will be in series with 8 kilo -ooms.
03:20
So equivalent resistance of this circuit that is 8 plus 4 -kilome means this is 12 kilo -oom.
03:31
Then in the second circuit, circuit b, 800 and 1 ,200 -oom, these are in series...