1. In a distance time graph based on the motion of a car- (a) What type of motion does a car show which is not moving with a constant speed? (b) What type of motion does a straight line represents? (c) How is the average speed of the car different from its speed?
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- A car not moving with constant speed shows non-uniform motion. This means the speed of the car changes over time. Show more…
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1. What can you infer from the motion of the car in the illustration above? _____________________________________ Assuming that the position of the car is at equal intervals of time. (Describe the motion by using the following motion descriptors and choosing from the description – increases, decreases, constant, uniform) a. distance ___________________________________________________ b. speed _____________________________________________________ c. velocity ____________________________________________________ d. acceleration ________________________________________________ 2. How does the graph for constant acceleration look like? (Describe the shape of the graph – you can choose from parabolic, straight-line graph inclined to the left or right, straight-horizontal or straight vertical line graph) a. Position x versus time t ________________________________________ b. Velocity v versus time t ________________________________________ c. Acceleration a versus time t _____________________________________ 3. Give the value of the acceleration of the car in m/s^2. ______________________ 4. What do the graphs tell you about the motion of the car?
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Q.2 The distance-time graph of two trains is given below. The trains start simultaneously in the same direction. (a) How much ahead of A is B when the motion starts? (b) What is the speed of B? (c) When and where will A catch B? (d) What is the difference between speeds of A and B? (e) Is the speed of both the trains uniform or non-uniform? Justify your answer. Q.3 The motion of a train is described by the velocity-time graph as shown in the figure given below. Find displacement of car between 1. 0 to 20 s 2. 20 s to 50 s
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A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by $x(t)=b t^{2}-c t^{3},$ where $b=240 \mathrm{m} / \mathrm{s}^{2}$ and $c=0.120 \mathrm{m} / \mathrm{s}^{3}$ . (a) Calculate the average velocity of the car for the time interval $t=0$ to $t=10.0 \mathrm{s}$ . (b) Calculate the instantaneous velocity of the car at $t=0, t=5.0 \mathrm{s},$ and $t=10.0 \mathrm{s} .$ (c) How long after starting from rest is the car again at rest?
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