1 in a population of 2000 vipers 240 individuals express the...

In a population of 2000 vipers, 240 individuals express the recessive phenotype of non-poisonous (genotype = tt) while the remaining 1760 individuals express the dominant phenotype of poisonous (genotype = TT or Tt). a) Assuming that this population is in Hardy-Weinberg equilibrium, determine the frequencies of the T and t alleles. b) How many of the individuals expressing the dominant phenotype are homozygous, and how many are heterozygous?

Transcript

00:01 In the population of 200 ,000 wipers, there are 240 wipers that express the recessive type which is a non -poisonous one.

00:15 On the other hand, there are 1760 phenotypes that are dominant and express in the poisonous phenotype.

00:26 So now we need to find out assuming that the population follows.

00:33 The hw equation that is hardy -wingberg law p plus q is 1 or p -square plus 2 pq plus q is equal to 1 so assuming this we have to determine the frequency of allele t and t into we need to find out frequency of dominant and recessive allail and also along with that we need to determine that how many individuals are going to express the homozygous and heterozygous dominant phenotype.

01:20 Meaning how many individuals will have either this or this type of genotypes.

01:27 So let's start.

01:28 So one thing we know that number of or the allele frequency can be determined by the equation that is number of copies of a given allele.

01:43 Suppose we are taking of this allele upon the total number of population.

01:51 So when you are talking about t, it would be how we have 1760 individuals amongst the 2000 population, which gives you 0 .88 as a frequency.

02:05 So t square is equal to 0 .8.

02:08 And when you talk about the recessive one we have 240 individuals in the total population of 2000 giving you the answer of 0 .12 so we have got the allele frequency now going to the second section that is where we know that t square and so we know this t square and this this t square so keeping this in an equation p plus q is equal to 1 p is the dominant one so this will be t and this will be small t so let's find out the values so p would be 1 minus q which is for that we need to know the q so how will we determine the q would be simply under root 0 .12 that is t so t is equal to 0 .34 so put the values p is equal to 1 minus 0 .34 give you 0 .6 so now you got what is p and what is q so now we have our p and q so we got the answer for this moving for this answer so p and q values were needed because we are going to use the equation p square plus 2 p q plus q plus q square is equal to 1 because we need to find out the heterogous conditions here so for heterogous you needed the value of p and q so p square and q square that is this we are already aware of so now let's put the values p square is 0 .66 to this power 2 plus 2 multiplied by 0 .6x multiplied by 0 .34 plus q is 0 .34 to the power square.

04:20 So now we know this is what q this is p...

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