00:01
The question that is given over here it says that there are two questions given and we have to answer the questions one by one.
00:06
The first question is we have to calculate the number of lamb and the disposition is it is required to provide an elimination of 100 lux in a factory hall with 30 meter into 12 meter.
00:24
We have to assume that the differentiation factor is 0 .8 and the coefficient of utilization factor is 0 .8 and the coefficient of you.
00:30
The efficiency of proposal lamp is 14 lm per watt.
00:49
We know the given so we can calculate the number of lam required.
00:56
The formula is 5 will be equal to e into a divided by uf into df.
01:15
Substituting, we get 100 into 360 divided by 0 .4.
01:22
Into 0 .8 that will be equal to 72 ,000.
01:33
Then the number of lamp required will be equal to 72 ,000 divided by 14 into 200 into 257 and that will be equal to 26 lamp.
01:59
So number of 100 watt lamp will be equal to 51 we get it by 72 ,000 divided by 14 into hundreds that will be equal 7 51 the next question given over here it says that a workshop is 100 meter into 15 meters is to be eliminated with intensity of elimination being 50 lus we have to determine the number of lamps and design a suitable scheme of lighting if the coefficient of utilization is 0 .9 and maintenance factor is 0 .7 and the efficiency of clamp is 80 lumen per watt.
02:50
So let us calculate the gross lumen for which the same formula 100 into 50 into 50 divided by 0 .9 into 1 by 0 .7...