Question

1) \( \left(\frac{11}{18}-\frac{4}{9}\right) \cdot \frac{3}{16} \); 4) \( 1 \frac{3}{5} \cdot \frac{3}{4}+1 \frac{3}{8} \); 2) \( \frac{11}{18}-\frac{4}{9} \cdot \frac{3}{16} \); 5) \( 1 \frac{3}{25} \cdot 2 \frac{1}{7}-2 \frac{1}{9} \cdot \frac{27}{190} \); 3) \( 1 \frac{3}{5} \cdot\left(\frac{3}{4}+1 \frac{3}{8}\right) \); 6) \( \left(8-2 \frac{1}{7} \cdot 3 \frac{1}{9}\right) \cdot \frac{27}{44} \) !

          1) \( \left(\frac{11}{18}-\frac{4}{9}\right) \cdot \frac{3}{16} \);
4) \( 1 \frac{3}{5} \cdot \frac{3}{4}+1 \frac{3}{8} \);
2) \( \frac{11}{18}-\frac{4}{9} \cdot \frac{3}{16} \);
5) \( 1 \frac{3}{25} \cdot 2 \frac{1}{7}-2 \frac{1}{9} \cdot \frac{27}{190} \);
3) \( 1 \frac{3}{5} \cdot\left(\frac{3}{4}+1 \frac{3}{8}\right) \);
6) \( \left(8-2 \frac{1}{7} \cdot 3 \frac{1}{9}\right) \cdot \frac{27}{44} \) !

1) ((11)/(18)-(4)/(9)) ·(3)/(16);
4) 1 (3)/(5)·(3)/(4)+1 (3)/(8);
2) (11)/(18)-(4)/(9)·(3)/(16);
5) 1 (3)/(25)· 2 (1)/(7)-2 (1)/(9)·(27)/(190);
3) 1 (3)/(5)·((3)/(4)+1 (3)/(8));
6) (8-2 (1)/(7)· 3 (1)/(9)) ·(27)/(44) !

Added by Julian H.

Prealgebra & Introductory Algebra

Julie Miller, Molly O'Neill, Nancy Hyde 2nd Edition

Chapter 4

Instant Answer

Solved by Expert Jacob Fry

Step 1

- Convert \(\frac{4}{9}\) to have a common denominator with \(\frac{11}{18}\): \(\frac{4}{9} = \frac{8}{18}\). - Subtract: \(\frac{11}{18} - \frac{8}{18} = \frac{3}{18} = \frac{1}{6}\). - Multiply: \(\frac{1}{6} \cdot \frac{3}{16} = \frac{3}{96} = \frac{1}{32}\). Show more…

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Thanks for your feedback!

1) \( \left(\frac{11}{18}-\frac{4}{9}\right) \cdot \frac{3}{16} \); 4) \( 1 \frac{3}{5} \cdot \frac{3}{4}+1 \frac{3}{8} \); 2) \( \frac{11}{18}-\frac{4}{9} \cdot \frac{3}{16} \); 5) \( 1 \frac{3}{25} \cdot 2 \frac{1}{7}-2 \frac{1}{9} \cdot \frac{27}{190} \); 3) \( 1 \frac{3}{5} \cdot\left(\frac{3}{4}+1 \frac{3}{8}\right) \); 6) \( \left(8-2 \frac{1}{7} \cdot 3 \frac{1}{9}\right) \cdot \frac{27}{44} \) !