00:01
For this problem, we are told to let t3 be the mclaurin polynomial of f of x equals e to the power of x.
00:07
We are then asked to use the error bound to find the maximum possible value of the error between the function evaluated at 1 .1 and the mclaurin polynomial evaluated at 1 .1.
00:20
And we're asked to show that we can take k to equal e to the power of 1 .1.
00:25
So we'll first note that t3 is going to be just 1 plus x plus x squared over 2 factorial, plus x cubed over 3 factorial.
00:37
Also know that the error there, f of 1 .1 minus t3 of 1 .1, is going to be less than or equal, less than or equal, to k times the absolute value of x minus.
00:52
Now, our a is going to be 0, so x minus 0, so it's going to be 1 .1 minus 0, to the power of n plus 1, divided by n plus 1 factorial.
01:06
So n plus 1 is going to be 4, we are dividing by 4 factorial.
01:12
Now that k, we have that the n plus 1th derivative evaluated at some point you, has to be less than or equal to k...