Question

(1) Liquid X has a melting point of 32°C and a specific heat of 3.36 J/g °C. 200 grams of liquid X are heated to a temperature of 68°C. Then 35.0 grams of solid X @ 32°C are added to the warm liquid X. The temperature of the mixture soon stabilizes at 54°C. Based on this information, what is the heat of fusion for solid X?

          (1) Liquid X has a melting point of 32°C and a specific heat of 3.36 J/g °C.
200 grams of liquid X are heated to a temperature of 68°C. Then 35.0 grams
of solid X @ 32°C are added to the warm liquid X. The temperature of the
mixture soon stabilizes at 54°C. Based on this information, what is the heat
of fusion for solid X?

(1) Liquid X has a melting point of 32°C and a specific heat of 3.36 J/g °C.
200 grams of liquid X are heated to a temperature of 68°C. Then 35.0 grams
of solid X @ 32°C are added to the warm liquid X. The temperature of the
mixture soon stabilizes at 54°C. Based on this information, what is the heat
of fusion for solid X?

Added by Allen P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Shaiju T

Step 1

The formula to calculate the heat absorbed is: Q = m * c * ΔT Where: Q = heat absorbed (in Joules) m = mass of the substance (in grams) c = specific heat of the substance (in J/g°C) ΔT = change in temperature (in °C) Using the given values: m = 200 grams c = Show more…

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Liquid X has a melting point of 32Â°C and a specific heat of 3.36 J/gÂ°C. 200 grams of liquid X are heated to a temperature of 68Â°C. Then 35.0 grams of solid X @ 32Â°C are added to the warm liquid X. The temperature of the mixture soon stabilizes at 54Â°C. Based on this information, what is the heat of fusion for solid X?