(1 point) A rock is dropped from a height of 39 feet. Its velocity in feet per second at time $t$ after it is dropped is given by $s(t) = -32t$ where time $t$ is measured in seconds. How far is the rock from the ground one second after it is dropped? The rock is feet from the ground one second after it is dropped.
Added by Nicol-S Z.
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To find the distance the rock has fallen after 1 second, we substitute $t=1$ into the equation. Show more…
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