00:01
We have given here x is equal to rho sin phi cos theta, y is equal to we have here rho sin phi sin theta, z is equal to we have given here rho cos.
00:28
So now we need to find here that is determinant of del of x, y, z upon we have here del rho, phi, theta and determinant of close that is equal to then we have here determinant of del x upon del rho, del x upon del phi and del x upon del theta.
01:27
Next we have here, del y upon del rho, del x upon del phi, del x upon del theta.
01:37
Next is we have here, del z upon del rho, we have here del y, also here del y.
01:50
And next is del z upon del phi and that is del z upon del theta.
02:03
So after putting here value, our function will be that is equal to determinant of sin phi into cos theta, rho cos phi cos theta minus rho sin phi sin theta.
02:25
Now next we have here sin phi sin theta.
02:36
Next will be rho cos theta sin cos phi sin theta.
02:46
And the value of dy by d theta is rho sin phi sin cos theta.
03:02
Now del z upon del rho will be cos phi.
03:05
This will be minus of rho sin phi...