Question

(1 point) Evaluate the integral. tilde(A)◻hat(A)C for the arbitrary constant. Absorb into C as muÃ ◻hat(A)◻ h as possible.A◻hat(A) \int (1)/(x(x-9)^(2))dx= Evaluate the integral. $\int \frac{1}{x(x-9)^2} dx$ =

Name: 1 point evaluate the integral tildeahatac for the arbitrary constant absorb into c as mua hata h as possibleahata int 1xx 92dx evaluate the integral int frac1xx 92 dx 54517
Uploaded: 2023-12-12T16:31:14-08:00
Duration: 4 min 28 s
Channel: H M
Description: 1 point evaluate the integral tildeahatac for the arbitrary constant absorb into c as mua hata h as possibleahata int 1xx 92dx evaluate the integral int frac1xx 92 dx 54517

          (1 point)
Evaluate the integral.
tilde(A)◻hat(A)C for the arbitrary constant. Absorb into C as muÃ ◻hat(A)◻ h as possible.A◻hat(A)
\int (1)/(x(x-9)^(2))dx=
Evaluate the integral.
$\int \frac{1}{x(x-9)^2} dx$ =

$1 point evaluate the integral tildeahatac for the arbitrary constant absorb into c as mua hata h as possibleahata int 1xx 92dx evaluate the integral int frac1xx 92 dx 54517$

Added by Tracy V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert H M

12/12/2023

Step 1

We have $$ \frac{1}{x(x-9)^2} = \frac{A}{x} + \frac{B}{x-9} + \frac{C}{(x-9)^2} $$ Multiplying both sides by $x(x-9)^2$, we get $$ 1 = A(x-9)^2 + Bx(x-9) + Cx $$ Let $x=0$. Then $1 = 81A$, so $A = \frac{1}{81}$. Let $x=9$. Then $1 = 9C$, so $C = \frac{1}{9}$. Let Show more…

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(1 point) Evaluate the integral. tilde(A)◻hat(A)C for the arbitrary constant. Absorb into C as muÃ ◻hat(A)◻ h as possible.A◻hat(A) \int (1)/(x(x-9)^(2))dx= Evaluate the integral. $\int \frac{1}{x(x-9)^2} dx$ =