00:01
Question we say for each of the following vector fields f we want to determine whether it is conservative or not by computing the appropriate first order partial derivatives.
00:10
Then we're going to type in a potential function little f such that the gradient of little f is equal to capital f with f of 0 0 equaling 0 if it is conservative and if it's not conservative we type n.
00:23
So i want to just review the criteria for being conservative which is down here in blue.
00:30
If we have a vector field f which is pi plus qj then in order for the vector field to be conservative it must be true that the partial of p with respect to y is equal to the partial of q with respect to x.
00:46
So let's take a look at vector field a.
00:50
So in a we have p and we have q right.
00:54
So first of all what is my partial of p with respect to y? that would be 6.
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How about my partial of q with respect to x? that would be 6 as well.
01:09
So this is conservative.
01:12
That means this is the gradient of some potential function f.
01:18
So f sub x is equal to negative 16 x plus 6 y while f sub y is 6 x plus 16 y.
01:31
So what does this tell you about f? well if i integrate with respect to x i get negative 8 x squared plus i'm gonna have 6 x y.
01:45
Whereas over here and it's plus some other function that is a function of y alone so plus some g over y.
01:55
Whereas over here i'm integrating with respect to y.
01:58
I'm gonna get 6 x y plus 8 y squared plus some function of x.
02:08
And so if i put this together what am i getting for f of x y? i'm getting negative 8 x squared and then it's plus 6 x y and then it's plus 8 y squared.
02:26
That would be my answer for part a.
02:30
Now in b i have f of x y equals negative 8 y minus 7 x...