00:01
The given matrix that is 4, 6, negative 3, negative 5 to find eigenvalues and eigenvectors.
00:21
So first find the eigenvalue that is a negative lambda i is equal to 0.
00:25
It implies determinant of 4 negative lambda 6 negative 3 negative 5 negative lambda is equal to 0.
00:33
It implies 4 negative lambda multiplied to negative 5 negative lambda plus 18 is equal to 0.
00:41
It implies lambda square plus lambda negative 20 plus 18 is equal to 0.
00:51
It implies lambda square plus lambda negative 2 is equal to 0.
00:56
So from here lambda plus 2 multiplied to lambda negative 1 is equal to 0.
01:00
It implies lambda is equal to 1 and negative 2.
01:03
Therefore our eigenvalues are lambda is equal to 1 and negative 2.
01:15
So this is our required answer.
01:17
Now we need to find the eigenvectors.
01:21
Now the eigenvector 1 corresponding to eigenvalue 1.
01:26
That is the matrix will be subtract the 1 in the diagonal entry.
01:31
It will give 3, 6, negative 3 and negative 6.
01:35
Here will be the vector x and y.
01:39
This product will be 0 0.
01:41
So now multiply the vector this vector to this matrix...