00:02
In this question, we are given a range of function f of x as 1 over x squared to 1 over x.
00:10
We need to check whether the given integrals converge or diverge.
00:17
Now, the first given integral is integral from 1 to infinity, square root of x, f of x, dx.
00:26
Now we know that f of x less than equal to g of f converges or diverges, accordingly if g of x converges or diverges.
00:50
Now, from the given function, we will take the value of f of x as 1 over x, that is 1 to infinity square root of x, 1 over x, dx.
01:03
That is 1 to infinity 1 over square root of x d x this gives 1 to infinity x x x x x x x x x x to per negative of 1 over 2 d x integrating a get x x to per 1 over 2 over 2 and limit x approaches to infinity that is limit x approaches to infinity 2 times square root of x this one clearly diverges x x approaches to to infinity.
01:38
Therefore, f of x also diverges.
01:41
This is the solution for the first subpart.
01:44
Further, the second given integral is 1 to infinity 0 .00001 times f of x dx.
02:00
That is equal to 1 to infinity f of x over 10 raised to par 6 d x...