00:01
Hi, now we are going to find the parametric equation or vector of t to the line segment c.
00:08
Now here the given point p is 5 ,0 and the point q is 0 ,3.
00:16
I take 5 ,0 as x1 ,y1 and 0 ,3 as x2 ,y2.
00:25
So now here we have the equation will be x -5 divided by 0 -5 is equal to 5 -0 divided by 3 -0 is equal to t.
00:39
So from this we can write x -5 is equal to –5t.
00:43
So x will be equal to 5 -5t and we can write y is equal to 3t.
00:51
Therefore here we have or vector of t is equal to 5 -5t ,3t where 0 less than or equal to t less than or equal to 1.
01:06
And next in part b we are going to find integral over c f dot dr.
01:11
Now here the given f vector is equal to –y ,x.
01:18
So we have to find f vector of or vector of t and this will be equal to –3t ,5 -5t and then we have to find or dash of t and this will be –5 ,3.
01:44
Then we can write integral over c f vector dot dr vector is equal to integral over a to b f vector of or vector of t into or vector dash of t into dt is equal to integral from a to b –3t ,5 -5t dot product with –5 ,3 into dt.
02:19
So this will be equal to integral from a to b 15t plus 15 minus 15t into dt...