00:01
In this problem, we want to use cylindrical shells to find the volume of a solid generated by rotating a region about the y -axis.
00:08
And this specific region is going to be formed by the bounds, y -equals e to the x -squared, x -equals 1, x -equal square -to -3, and y -equal 0.
00:23
So what does this look like? so 1 is less than square to 3 because the squareer to 1 is equal to 1.
00:33
So we're going to have, say, here's x equals 1, and here's x equals square to 3.
00:44
And here's my x -axis, which is the same as y -equal -0.
00:48
So then this is just kind of a rough sketch.
00:50
I don't really know what this curve looks like exactly, but it's going to curve up in some way, probably much faster than your normal exponential function, because we have x squared instead of just x.
01:04
So here's my region, and i want to use cylindrical shells.
01:08
So the height of the shell is going to be formed by this y equals e to the x squared curve, and then we're going to be integrating dx here.
01:28
So my formula for the shell is going to be v equals the integral of 2 pi, x, f of x...