(1 point) Let f(w, z) = e^w \ln(z). (a) Use difference quotients with h = 0.02 to approximate each of the partial derivatives: f_w(4, 4) \approx f_z(4, 4) \approx (b) Now evaluate the partial derivatives exactly: f_w(4, 4) = f_z(4, 4) =
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02, 4) - f(4,4)] / 0.02 fw(4,4) ≈ [e^(4*4) - e^(4*4)] / 0.02 fw(4,4) ≈ [e^16 - e^16] / 0.02 fw(4,4) ≈ 0 For the partial derivative with respect to z: fz(4,4) ≈ [f(4, 4+0.02) - f(4,4)] / 0.02 fz(4,4) ≈ [e^(4*4) - e^(4*4)] / 0.02 fz(4,4) ≈ [e^16 - e^16] / Show more…
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