Question

(1 point) Suppose the angle A satisfies $0 < A \le 2\pi$. If $cos(A) = -0.87$ and $sin(A) > 0$, determine: The quadrant for the angle A/2 = Quadrant? Then, $sin(A) = $ $sin(A/2) = $ $cos(A/2) = $ $tan(A/2) = $ Be certain to express all answers to at least four decimal places.

          (1 point) Suppose the angle A satisfies $0 < A \le 2\pi$.
If $cos(A) = -0.87$ and $sin(A) > 0$, determine:
The quadrant for the angle A/2 = Quadrant?
Then,
$sin(A) = $
$sin(A/2) = $
$cos(A/2) = $
$tan(A/2) = $
Be certain to express all answers to at least four decimal places.
        
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(1 point) Suppose the angle A satisfies 0 < A ≤ 2π.
If cos(A) = -0.87 and sin(A) > 0, determine:
The quadrant for the angle A/2 = Quadrant?
Then,
sin(A) =
sin(A/2) =
cos(A/2) =
tan(A/2) =
Be certain to express all answers to at least four decimal places.

Added by Miguel G.

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Introductory and Intermediate Algebra for College Students 4th
Introductory and Intermediate Algebra for College Students 4th
Robert Blitzer 4th Edition
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1 pointSuppose the angle A satisfies 0<A<2TT If cosA=-0.87 and sinA>0,determine: The quadrant for the angleA/2= Quadrant? Then, sin(A)= sin(A/2= cos(A/2= tan(A/2) Be certain to express all answers to at least four decimal places.
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Transcript

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00:01 So we're given the cosine of a, and that's negative 0 .79.
00:06 And we're told the sine of a is greater than 0.
00:10 Cosine is negative and sine is positive, that means a is in quadrant 2, which is between pi over 2 and pi.
00:23 We want to first determine the quadrant for a over 2.
00:29 So if a is between pi and pi over 2, then we're just going to divide everything by a half, and that tells me that the half angle is between pi over 2 and pi over 4.
00:48 So that half angle is in quadrant 1.
00:58 Now i want the sine of a.
01:02 So if my cosine is negative 0 .79, that's another way of saying negative 79 over 100...
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