1. Show that the first order ODE (2xy + 3x^2)dx + (x^2 - 1)dy = 0 is exact. Then use the appropriate method to find the general solution.
Added by Manuel W.
Close
Step 1
We can do this by using the quadratic equation method. We first need to find the roots of the equation. We can do this by using the quadratic equation method. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 67 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Show that the equation is not exact, then find an appropriate integrating factor and solve: (3x^2y + 2xy + y^3)dx + (x^2 + y^2)dy = 0.
Madhur L.
Verify that the equation x^2y^3 + x(1 + y^2)y′ = 0 is not exact and that it becomes exact when multiplied by the integrating factor µ(x, y) = 1/xy^3 Finally solve the differential equation
David N.
dy/dx = (3x^2 + 4x + 2) / (2(y - 1)) y(0) = -1 Find the general solution of the above differential equation.
Vishal P.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD