We can rewrite this as:
y' = \frac{y + x}{x - y}
Now, let v = \frac{y}{x}. Then, y = xv and y' = v + xv'. Substituting these into the equation, we get:
v + xv' = \frac{xv + x}{x - xv}
Now, we can solve for v':
xv' = \frac{x^2v}{1 - v} - v
v' = \frac{xv}{1 -
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