Question

1) State the interval for which the function $f(x) = sqrt{16 - x^2}$ is Continuous. 2) Consider the following table egin{tabular}{|c|c|} hline x & f(x) \ hline 2.9 & 9.62 \ 2.99 & 9.85 \ 2.999 & 9.99 \ 3.001 & 9.99 \ 3.01 & 9.85 \ 3.1 & 9.62 \ hline end{tabular} What is the reasonable estimate for $lim_{x o 3} f(x)$? a) 2.9 b) 3 c) 9.9 d) 10 3) The value of $lim_{x o 0} e^{sin x} = $

          1) State the interval for which the function $f(x) = sqrt{16 - x^2}$ is
Continuous.
2)
Consider the following table
egin{tabular}{|c|c|}
hline
x & f(x) \
hline
2.9 & 9.62 \
2.99 & 9.85 \
2.999 & 9.99 \
3.001 & 9.99 \
3.01 & 9.85 \
3.1 & 9.62 \
hline
end{tabular}
What is the reasonable estimate for $lim_{x 	o 3} f(x)$?
a) 2.9
b) 3
c) 9.9
d) 10
3) The value of $lim_{x 	o 0} e^{sin x} = $

1) State the interval for which the function f(x) = sqrt16 - x^2 is
Continuous.
2)
Consider the following table
egintabular|c|c|
hline
x f(x) hline
2.9 9.62 2.99 9.85 2.999 9.99 3.001 9.99 3.01 9.85 3.1 9.62 hline
endtabular
What is the reasonable estimate for limx o 3 f(x)?
a) 2.9
b) 3
c) 9.9
d) 10
3) The value of limx o 0 e^sin x =

Added by Teresa Z.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

02/27/2023

Step 1

So, we need to find the interval for which 16-x \geq 0. 16-x \geq 0 x \leq 16 So, the function is continuous for the interval x \in (-\infty, 16]. 2) To estimate the limit of f(x) as x approaches 2.999, we can look at the values of f(x) in the table that are Show more…

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1) State the interval for which the function f(x) = ∑(16 - x^2) is continuous. 2) Consider the following table: x | f(x) 2.9 | 9.62 2.99 | 9.85 2.999 | 9.99 3.001 | 9.99 3.01 | 9.85 3.1 | 9.62 What is the reasonable estimate for lim x→3 f(x)? a) 2.9 b) 3 c) 9.9 d) 10 3) The value of lim x→0 e^sin x =