1 the gas phase decomposition of sulfuryl chloride at 600 k...

1. The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g) -> SO2(g) + Cl2(g) is first order in SO2Cl2 with a rate constant of 2.80×10^-3 min^-1. If the initial concentration of SO2Cl2 is 4.90×10^-3 M, the concentration of SO2Cl2 will be _______M ?? after 521 min have passed. 2. The gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g) -> 2NO2(g) + ½ O2(g) is first order in N2O5 with a rate constant of 4.70×10^-3 s^-1. If the initial concentration of N2O5 is 3.94×10^-2 M, the concentration of N2O5 will be 7.56×10^-3 M after _______ s ??? have passed.

Transcript

00:01 Hello students, welcome here.

00:01 In this question there are two parts.

00:03 So the first part they are asking here it is a gas decomposed of sulfuride.

00:10 So here the gas is given so2 cl2 gas is decomposed to so2 gas plus cl2 gas.

00:23 So it is a first -order reaction.

00:26 So the initial concentrations are given.

00:28 So the initial concentrations are given.

00:29 So the initial concentration is given as 4 .90 multiple minus 3 and rate constant is given 2 .08 multiplied by 10 power minus 3 so after time t 521 minutes here meeting minute inverse is given so after 521 minutes what is the concentration of the copso 2 clt we had to calculate the final concentration so here it is equal to as it is a first -order reaction lna is equal to lna not minus kt is the equation for this one so lna is equal to ln 4 .90 multiplied by 10 power minus 3 minus k is 2 .08 multiplied by 10 power minus 3 t is 521 minutes so here lna is equal to minus 6 .40 we will get.

01:40 Now a concentration of a is equal to it is exponential power minus 6 .40.

01:49 So that is equal to 1 .66 multiplied by 10 power minus 3m is the concentration of so2 cl2 after of 521 minutes okay so this one is a final in final concentration we got another question is given here this one is n -2 o5 is given so it is decomposed to n -o2 and half o2 so n2 o5 is decomposed to 2n -o2 and half o2 so here initial concentration are given so that is 3 .94 multiplied by 10 power minus 2.

02:36 And final concentration also given here, it is 7 .56 10 power minus 3 is given...

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