1. The two charges in the figure below are separated by d = 4.00 cm. (Let q1 = -15.5 nC and q2 = 29.5 nC.) (a) Find the electric potential at point A. (b) Find the electric potential at point B, which is halfway between the charges.
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The electric potential V due to a point charge q at a distance r is given by the formula: V = k * q / r where k is the electrostatic constant, approximately 8.99 * 10^9 N m^2/C^2. For q1, the distance r1 from point B is half of the distance d, so r1 = 0.02 m. Show more…
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