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Hello everyone in this problem constructive frequency distribution for the given data.
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So here we have class 20 to 26 27 to 33 34 to 40 41 to 47 47 48 to 54 and here we have frequency 5 7 6 6 7, 5 and total is 30 and for the next construct a frequency distribution for the given data using 5 classes and we have to draw frequency histogram frequency polygon and ojive so first of all we draw histogram for this data so firstly we draw y -axis over here this is our y -axis and this is our x -axis now here we have zero four five six seven and eight this is our y -axis and here we have twenty twenty six thirty -three forty -seven 54 xx.
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So here we draw kink because the interval is unequal.
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And in this place also we draw a kink.
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Now to draw this, this is the frequency of 5.
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So we draw up to the height of 5 from both the sides from 20 to 26.
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Now, join.
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In joining these two.
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Now, for the next we have seven.
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So we draw up to the height of 7 and for this point also we draw up to the height of 7.
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Now joining these 2.
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For next, we have up to the height of 6.
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So now, joining these 2.
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Next is again up to the height of 6.
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The height of 7.
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So from here also we extend this up to the height of 7.
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Now joining these two.
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Now again it is up to 5.
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So now we joining this as 5.
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Here we take class boundaries, class boundaries and here we have frequency in the next.
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Now for the frequency polygon for polygon draw y -axis.
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So this is our y -axis and here we have the x -axis.
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We draw over here.
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This is our 0, 23, 30, 37, 44, 51, and here we have 4, 8, here we have 4, 5, next 6, then 7, 8.
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This is our y -axis, x -6s, here we have class mid -points, mid -points, and here we have frequency.
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In the first, here we draw kink over both the sides.
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Now, at 23, we have 5, then 7.
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We have 7.
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Next is 6, next 6, then 7, then next is 5.
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Then next is 5.
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Now, we're joining these points, joining these points, we get our polygons.
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Polygon now join this on the ground this is our required polygon now for for the ojive we take this as y xx this is our y x and here we take xx and this is our xx and this is our x xx is so this is 0 20 .5 26 .5 33 .5, 40 .5, 47 .5, 54 .5.
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So we have 54 .5.
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Now, for this, here we have 5, 10, 15, 20, 25, 25, and 35, and 30, and 30, and 30.
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So from here we have 5.
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Next is 10.
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Next is from this point we have 10.
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And from the next we have 18.
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For next we have 25 and then 30.
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Now joining these by joining these dots we get our required...