00:01
So, in this question, to answer this question, let's go step by step.
00:03
So the first one is the size of the main memory.
00:05
So the number of blocks in the main memory can be determined by the number of bits in the block address.
00:12
So in this case, each block is one word, 4 bytes, and the set associativity mapping is two -way or there are two sets.
00:20
So the number of blocks in each set is given by the set number.
00:23
And the block size is 4 bytes and there are two sets.
00:26
So therefore, the number of blocks in each set is 2.
00:31
And the main memory size is 2 multiplied by 2 multiplied by 4, which is 16 bytes.
00:35
Now coming to the size of cache memory.
00:38
So in this, the size of cache memory is determined by the number of sets, the number of blocks in each set and the block size.
00:44
So 2 multiplied by 2 multiplied by 4, which is 16 bytes.
00:48
Now coming to the reading memory address 16.
00:50
So reading 16 belongs to set 1, block 1, and the tag for this block is 00...