00:01
Hi, in the first question we are given with the value of diameter, length and elastic modulus.
00:05
So, we have torsional spring constant.
00:09
So, torsional spring constant is given by it is t by q.
00:18
So, this is given by g t by l.
00:21
So, now on substituting the given values we have g as 79 into 10 power 3 mega pascal into t is.
00:29
So, this is i.
00:31
So, i is pi by 32 into 3 .15 whole power 4 that is pi by.
00:37
So, this is the term moment of inertia divided by l length is given as 300 millimeter.
00:43
So, from this calculation we have the torsional spring constant is equal to.
00:50
So, it is 2545 .35 newton millimeter.
00:56
Then in the second part of the question we are given with the polar moment of inertia and torsional stiffness.
01:02
So, there is a small displacement.
01:06
So, theta with a small displacement is given to the system.
01:13
Then we have by d 'alembert's principle.
01:16
So, using d 'alembert's principle taking the moment along o we have j naught into...