When substrate concentration is much lower than KM, the rate of catalysis is A) (Vmax/KM)•[S] B) kcat C) Vmax D) Kmax E) KM/Vmax 2. Which of the following is true of competitive inhibition? A) The KM has no effect and the Vmax increases B) The KM increases and the Vmax doesn't change C) Inhibitor binds in an allosteric site. D) Inhibitor binds to the same site as the substrate E) Inhibitor binds only when the substrate is in the active site.
Added by Michelle L.
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Step 1: In the first question, when substrate concentration is much lower than KM, the rate of catalysis is determined by the equation V = (Vmax/KM)•[S]. Show more…
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