1. Write down the Michaelis-Menten equation. Define KM and Vmax. 2. At low substrate concentrations, an enzyme reaction will display __________ order kinetics. Use the graph on the right to answer the following two questions: 3. a) Which enzyme has the lower KM? b) Which enzyme has the higher affinity to the substrate? c) Which enzyme has the higher Vmax? 4. a) If the substrate concentration is at the value indicated by the arrow, which enzyme catalyzes the reaction faster? b) If the substrate concentration is at the value indicated by the dashed line arrow, which enzyme catalyzes the reaction faster?
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The Michaelis-Menten equation is given by: \[ v = \frac{V_{max} \cdot [S]}{K_m + [S]} \] where \( v \) is the rate of the enzyme reaction, \( V_{max} \) is the maximum rate of the reaction, \( [S] \) is the substrate concentration, and \( K_m \) is the Michaelis Show more…
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6. The following is a Michaelis-Menten curve. Label on this graph the following: - As [S] increases, the initial rate or velocity (V₀) increases (Label as A) - As [S] increases, V increases less and less (Label as B) - V no longer increases and velocity reaches its maximum (Label as C) Figure 1. The Michaelis-Menten curve describes the relationship between an enzyme (at constant concentration) and the concentration of substrate [S]. V₀ is the initial rate. Where on the graph (A, B, or C) is the enzyme saturated with substrate?
Supreeta N.
Both Enzyme A and Enzyme B act on substrate S and follow Michaelis-Menten Kinetics. Enzyme A has a greater KM for substrate S compared to Enzyme B. Assuming KM can be used to describe affinity for these relationship. Which enzyme has higher affinity for substrate S? Explain your answer. A) Enzyme A B) Enzyme B
Adi S.
Equation There are several ways to transform the MichaelisMenten equation so as to plot data and derive kinetic parameters, each with different advantages depending on the data set being analyzed. One transformation of the MichaelisMenten equation is the Lineweaver-Burk, or double-reciprocal, equation. Multiplying both sides of the Lineweaver-Burk equation by $V_{\max }$ and rearranging gives the Eadie-Hofstee equation:$$V_{0}=\left(-K_{\mathrm{m}}\right) \frac{V_{0}}{[\mathrm{S}]}+V_{\max }$$,A plot of $V_{0}$ versus $V_{0} /$ [S] for an enzyme-catalyzed reaction is shown below. The blue curve was obtained in the absence of inhibitor. Which of the other curves (A, B, or C) shows the enzyme activity when a competitive inhibitor was added to the reaction mixture? Hint: See Equation 6-30.(GRAPH CAN'T COPY)
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