00:01
In this problem, we have two questions.
00:03
The first one is b.
00:05
We are given this matrix c equal to 1, 1, 1, a, a, a, after a, b, c, a squared, b squared, c squared.
00:18
And we are going to find the inverse of this matrix c.
00:22
The inverse is given by the edge joint of this matrix divided by the determinant of this matrix.
00:31
So let's start with the determinant of this matrix.
00:36
Let us use the expansion with respect to the first row.
00:41
We have 1 times.
00:44
So we close this, close this and take the determinant of the rest.
00:49
Bc b squared c squared minus a times.
00:53
We close this, close this.
00:55
Determinant of the rest 1 1 b squared c squared plus a squared times 1 1 b c if we compute these sub determinants these smaller determinants we will arrive at minus a minus b a minus c b minus c okay for the edge joint we have the following so first we are going to build this structure let's in fact make it larger and whatever this matrix is we will take its transpose okay now this works like this we have this alternating pattern plus minus plus minus plus plus, minus, plus, minus, plus.
02:01
And we are going to put some determinants here.
02:04
For the first entry, we will do it like this...