00:01
In this problem, we have been given that a projectile is fired at a speed of 3 .58 meter per second at an angle of 36 degree with respect to the horizontal.
00:18
And we have to determine the vertical component of this velocity.
00:23
So here we can get the vertical component by using the projection.
00:27
So for that, let's make use of this right angle triangle.
00:30
And we use sine 36 degree to relate the vertical component to we and the hypotenuse representing the initial speed.
00:41
So from here we can get the vertical speed or the vertical projection of the speed as 3 .58 times sine 36 degree and that comes out to be 2 .1 meter per second.
00:55
So this is the vertical speed.
00:57
And in the next situation we have been given that.
01:00
There is a vertical spring and this vertical spring is having spring constant of 156 newtons per meter and a block of mass 0 .9 kilograms is suspended here so we need to determine the time period of oscillation of this block so according to the expression of time period we know that omega square x times m is equal to kx and from here we can get omega as root of k by m but we know that omega is also 2 pi by t so from here we can get the time period and that will be 2 pi root m by k so this will be 2 pi root of the mass that's 0 .9 over k that's 156 so here we observe that when we take the root of 0 .9 divided by 156 and we multiply this result with two times of pi.
02:04
We're gonna get here at the time period coming out to be 0 .48 seconds approximately.
02:12
So it's near to 477.
02:14
So let's write that approximate time period.
02:19
And now in the next situation, we have been given here.
02:25
There are a group of students and they perform an experiment based on newton's second law experiment.
02:33
And they are graphing their results for the force they apply and the acceleration that they observe on the card.
02:43
And using this, they obtain a linear fit line which is represented by the equation w2 is equal to ff plus m .e.
02:55
So as they are drawing the graph in which the representation is between the applied force and the exceiturates, so here we have to figure out which physical quantity will this wind receptor represent...