314 J/mol K), $T$ is the temperature in Kelvin, $V_f$ is the final volume, and $V_i$ is the initial volume.
For the first case:
$n = 5$ moles
$T = 200^\circ\text{C} + 273.15 = 473.15\text{K}$
$V_i = 1\text{L} = 0.001\text{m}^3$
$V_f = 5\text{L} =
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