Question

10. Find the work done by the force field F(x,y,z) = z i + x j + y k in moving a particle from the point (3, 0, 0) to the point (0, ?/2, 3) along (a) a straight line (b) the helix x = 3 cos t, y = t, z = 3 sin t 11–12 Show that F is a conservative vector field. Then find a function f such that F = ?f. 11. F(x,y) = (1 + xy)e^{xy} i + (e^y + x^2 e^{xy}) j

          10. Find the work done by the force field

    F(x,y,z) = z i + x j + y k

in moving a particle from the point (3, 0, 0) to the point (0, ?/2, 3) along
(a) a straight line
(b) the helix x = 3 cos t, y = t, z = 3 sin t

11–12 Show that F is a conservative vector field. Then find a function f such that F = ?f.

11. F(x,y) = (1 + xy)e^{xy} i + (e^y + x^2 e^{xy}) j
        
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10. Find the work done by the force field

    F(x,y,z) = z i + x j + y k

in moving a particle from the point (3, 0, 0) to the point (0, ?/2, 3) along
(a) a straight line
(b) the helix x = 3 cos t, y = t, z = 3 sin t

11–12 Show that F is a conservative vector field. Then find a function f such that F = ?f.

11. F(x,y) = (1 + xy)e^xy i + (e^y + x^2 e^xy) j

Added by Susan F.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Transcript

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00:01 Hi, here in this question we are given that the force f of xyz is equal to z i cap plus x j cap plus y k cap and the value is from 3 .00 to 0 pi by 2 and 3.
00:19 Now here we need to find the work done across a straight line and a halix.
00:23 So the work done on a straight line will be the point v equals to minus 3 pi by 2 and 3.
00:30 So x equals to 3 minus 3 t, y equals to pi by 2 times of t and z equals to 3 t, where 0 less than or equal to t less than or equal to 1.
00:41 So differentiating we have d x equals to minus 3dt, dy equals to pi by 2 and dz equals to 3dt.
00:51 Now, so the work done would be integration over the curve c, f .t, ds.
00:57 Now this is again equal to integral over c.
01:00 P of d x plus q of d y plus r of d z therefore here in our case we have wakdon equals to integration of 0 to 1 z d x plus x d y plus y d z therefore this is again equal to integration of 0 to 1 3 t multiplied with 3 d t plus 3 minus 3 t multiplied with pi by 2 times of d t plus pi by 2 times of t multiplied with 3d t now on simplifying this and integrating we have 9 t plus 3 pi by 2 and the value is from 0 to 1 now giving value and simplifying this here we can say that we got our first answer as work done equals to 3 pi by 2 minus 9 now similarly we need to calculate in a system of a halix so for halix here we have x equals to 3 cost t y equals to t and z equals to 3 sine t.
02:10 Therefore, here we have dx equals to minus 3 sine t, d -y equals to dt and dz equals to 3 cost t d t...
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