10. For each of these compound propositions, use the conditional-disjunction equivalence (Example 3) to find an equivalent compound proposition that does not involve conditionals.\na) $\neg p \to \neg q$\nb) $(p \lor q) \to \neg p$\nc) $(p \to \neg q) \to (\neg p \to q)$
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2. For each of these compound propositions, use the conditional-disjunction equivalence (Example 3) to find an equivalent compound proposition that does not involve conditionals. a) pp → pq b) (p ∨ q) → pp c) (p → pq) → (pp → q)
Tassha C.
For each of these compound propositions, use the conditional-disjunction equivalence (Example 3) to find an equivalent compound proposition that does not involve conditionals. a) ¬p → ¬q b) (p ∨ q) → ¬p c) (p → ¬q) → (¬p → q)
Professor M.
For each of these compound propositions, use the conditional-disjunction equivalence (Example 3$)$ to find an equivalent compound proposition that does not involve conditionals. a) $\neg p \rightarrow \neg q$ b) $(p \vee q) \rightarrow \neg p$ c) $(p \rightarrow \neg q) \rightarrow(\neg p \rightarrow q)$
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