00:02
Hi, now we are going to find the regarance relation.
00:05
The given question is y double dash minus xy dash plus xy equal to 0.
00:15
So let us take y equal to summation n varies from 0 to infinity, a n x per n be the solution.
00:32
Then y -dash will be summation n varies from 1 to infinity n, a .n x power n minus 1.
00:46
And y double dash will be summation n varies from 2 to infinity n into n minus 1 x power n minus 2a n.
01:01
Now we substitute these values in the given question then we get summation n varies from 2 to infinity n into n minus 1, a .n x power n minus 2 minus x into summation n varies from 1 to infinity n, a .n x power n minus 1 plus x into summation n varies from 1 to infinity n, n, a .n x power n minus 1 plus x into summation.
01:33
Summation n varies from 0 to infinity, a n x power n equal to 0.
01:46
And it will be equal to summation n varies from 0 to infinity n plus 2 into n plus 1 into a n plus 2 x power n minus summation n varies from 1 to infinity...