(10 points) Evaluate dz where C Z0 - +eie 0 < 0 < 2T Use the parametrization of C to evaluate the integral. Do not appeal to the Cauchy Theorem or any other theorem that says the answer is 0.
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We can use the standard parametrization for a circle centered at Z0 with radius r: z = Z0 + re^(it) where t is the parameter and ranges from 0 to 2π. In this case, Z0 = -e^(iπ/4) and r = 1. So, we have: z = -e^(iπ/4) + e^(it) Show more…
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